5(y-4)+7y=-32

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Solution for 5(y-4)+7y=-32 equation: 



5(y-4)+7y=-32

We move all terms to the left:

5(y-4)+7y-(-32)=0

We add all the numbers together, and all the variables

7y+5(y-4)+32=0

We multiply parentheses

7y+5y-20+32=0

We add all the numbers together, and all the variables

12y+12=0

We move all terms containing y to the left, all other terms to the right

12y=-12

y=-12/12

y=-1

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