5(y-4)-19y=-7(2y+1)

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Solution for 5(y-4)-19y=-7(2y+1) equation: 



5(y-4)-19y=-7(2y+1)

We move all terms to the left:

5(y-4)-19y-(-7(2y+1))=0

We add all the numbers together, and all the variables

-19y+5(y-4)-(-7(2y+1))=0

We multiply parentheses

-19y+5y-(-7(2y+1))-20=0



We calculate terms in parentheses: -(-7(2y+1)), so:

-7(2y+1)

We multiply parentheses

-14y-7

Back to the equation:

-(-14y-7)



We add all the numbers together, and all the variables

-14y-(-14y-7)-20=0

We get rid of parentheses

-14y+14y+7-20=0

We add all the numbers together, and all the variables

-13!=0

There is no solution for this equation

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