5(y-4)-2=-5(-5y+4)-4y

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Solution for 5(y-4)-2=-5(-5y+4)-4y equation: 



5(y-4)-2=-5(-5y+4)-4y

We move all terms to the left:

5(y-4)-2-(-5(-5y+4)-4y)=0

We multiply parentheses

5y-(-5(-5y+4)-4y)-20-2=0



We calculate terms in parentheses: -(-5(-5y+4)-4y), so:

-5(-5y+4)-4y

We add all the numbers together, and all the variables

-4y-5(-5y+4)

We multiply parentheses

-4y+25y-20

We add all the numbers together, and all the variables

21y-20

Back to the equation:

-(21y-20)



We add all the numbers together, and all the variables

5y-(21y-20)-22=0

We get rid of parentheses

5y-21y+20-22=0

We add all the numbers together, and all the variables

-16y-2=0

We move all terms containing y to the left, all other terms to the right

-16y=2

y=2/-16

y=-1/8

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