5(y-4)-y=4(y-5)

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Solution for 5(y-4)-y=4(y-5) equation:


Simplifying
5(y + -4) + -1y = 4(y + -5)

Reorder the terms:
5(-4 + y) + -1y = 4(y + -5)
(-4 * 5 + y * 5) + -1y = 4(y + -5)
(-20 + 5y) + -1y = 4(y + -5)

Combine like terms: 5y + -1y = 4y
-20 + 4y = 4(y + -5)

Reorder the terms:
-20 + 4y = 4(-5 + y)
-20 + 4y = (-5 * 4 + y * 4)
-20 + 4y = (-20 + 4y)

Add '20' to each side of the equation.
-20 + 20 + 4y = -20 + 20 + 4y

Combine like terms: -20 + 20 = 0
0 + 4y = -20 + 20 + 4y
4y = -20 + 20 + 4y

Combine like terms: -20 + 20 = 0
4y = 0 + 4y
4y = 4y

Add '-4y' to each side of the equation.
4y + -4y = 4y + -4y

Combine like terms: 4y + -4y = 0
0 = 4y + -4y

Combine like terms: 4y + -4y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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