5(y-4)=(72y+1)

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Solution for 5(y-4)=(72y+1) equation: 



5(y-4)=(72y+1)

We move all terms to the left:

5(y-4)-((72y+1))=0

We multiply parentheses

5y-((72y+1))-20=0



We calculate terms in parentheses: -((72y+1)), so:

(72y+1)

We get rid of parentheses

72y+1

Back to the equation:

-(72y+1)



We get rid of parentheses

5y-72y-1-20=0

We add all the numbers together, and all the variables

-67y-21=0

We move all terms containing y to the left, all other terms to the right

-67y=21

y=21/-67

y=-21/67

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