5(y-4)=3(2y+3)

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Solution for 5(y-4)=3(2y+3) equation: 



5(y-4)=3(2y+3)

We move all terms to the left:

5(y-4)-(3(2y+3))=0

We multiply parentheses

5y-(3(2y+3))-20=0



We calculate terms in parentheses: -(3(2y+3)), so:

3(2y+3)

We multiply parentheses

6y+9

Back to the equation:

-(6y+9)



We get rid of parentheses

5y-6y-9-20=0

We add all the numbers together, and all the variables

-1y-29=0

We move all terms containing y to the left, all other terms to the right

-y=29

y=29/-1

y=-29

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