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5(y-4)=3(y+7)-9
We move all terms to the left:
5(y-4)-(3(y+7)-9)=0
We multiply parentheses
5y-(3(y+7)-9)-20=0
We calculate terms in parentheses: -(3(y+7)-9), so:We get rid of parentheses
3(y+7)-9
We multiply parentheses
3y+21-9
We add all the numbers together, and all the variables
3y+12
Back to the equation:
-(3y+12)
5y-3y-12-20=0
We add all the numbers together, and all the variables
2y-32=0
We move all terms containing y to the left, all other terms to the right
2y=32
y=32/2
y=16
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