5(y-4)=7(2y+4)

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Solution for 5(y-4)=7(2y+4) equation: 



5(y-4)=7(2y+4)

We move all terms to the left:

5(y-4)-(7(2y+4))=0

We multiply parentheses

5y-(7(2y+4))-20=0



We calculate terms in parentheses: -(7(2y+4)), so:

7(2y+4)

We multiply parentheses

14y+28

Back to the equation:

-(14y+28)



We get rid of parentheses

5y-14y-28-20=0

We add all the numbers together, and all the variables

-9y-48=0

We move all terms containing y to the left, all other terms to the right

-9y=48

y=48/-9

y=-5+1/3

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