5(y-4)=7(y+1)

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Solution for 5(y-4)=7(y+1) equation: 



5(y-4)=7(y+1)

We move all terms to the left:

5(y-4)-(7(y+1))=0

We multiply parentheses

5y-(7(y+1))-20=0



We calculate terms in parentheses: -(7(y+1)), so:

7(y+1)

We multiply parentheses

7y+7

Back to the equation:

-(7y+7)



We get rid of parentheses

5y-7y-7-20=0

We add all the numbers together, and all the variables

-2y-27=0

We move all terms containing y to the left, all other terms to the right

-2y=27

y=27/-2

y=-13+1/2

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