5(y-5)-2=-3(-9y+3)-8y

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Solution for 5(y-5)-2=-3(-9y+3)-8y equation: 



5(y-5)-2=-3(-9y+3)-8y

We move all terms to the left:

5(y-5)-2-(-3(-9y+3)-8y)=0

We multiply parentheses

5y-(-3(-9y+3)-8y)-25-2=0



We calculate terms in parentheses: -(-3(-9y+3)-8y), so:

-3(-9y+3)-8y

We add all the numbers together, and all the variables

-8y-3(-9y+3)

We multiply parentheses

-8y+27y-9

We add all the numbers together, and all the variables

19y-9

Back to the equation:

-(19y-9)



We add all the numbers together, and all the variables

5y-(19y-9)-27=0

We get rid of parentheses

5y-19y+9-27=0

We add all the numbers together, and all the variables

-14y-18=0

We move all terms containing y to the left, all other terms to the right

-14y=18

y=18/-14

y=-1+2/7

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