5(y-6)+2(3y-4)=-10

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Solution for 5(y-6)+2(3y-4)=-10 equation: 



5(y-6)+2(3y-4)=-10

We move all terms to the left:

5(y-6)+2(3y-4)-(-10)=0

We add all the numbers together, and all the variables

5(y-6)+2(3y-4)+10=0

We multiply parentheses

5y+6y-30-8+10=0

We add all the numbers together, and all the variables

11y-28=0

We move all terms containing y to the left, all other terms to the right

11y=28

y=28/11

y=2+6/11

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