5(y-6)+39=3(15-y)+4y

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Solution for 5(y-6)+39=3(15-y)+4y equation: 



5(y-6)+39=3(15-y)+4y

We move all terms to the left:

5(y-6)+39-(3(15-y)+4y)=0

We add all the numbers together, and all the variables

5(y-6)-(3(-1y+15)+4y)+39=0

We multiply parentheses

5y-(3(-1y+15)+4y)-30+39=0



We calculate terms in parentheses: -(3(-1y+15)+4y), so:

3(-1y+15)+4y

We add all the numbers together, and all the variables

4y+3(-1y+15)

We multiply parentheses

4y-3y+45

We add all the numbers together, and all the variables

y+45

Back to the equation:

-(y+45)



We add all the numbers together, and all the variables

5y-(y+45)+9=0

We get rid of parentheses

5y-y-45+9=0

We add all the numbers together, and all the variables

4y-36=0

We move all terms containing y to the left, all other terms to the right

4y=36

y=36/4

y=9

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