5(y-6)+4y=-10(-y+9)

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Solution for 5(y-6)+4y=-10(-y+9) equation: 



5(y-6)+4y=-10(-y+9)

We move all terms to the left:

5(y-6)+4y-(-10(-y+9))=0

We add all the numbers together, and all the variables

5(y-6)+4y-(-10(-1y+9))=0

We add all the numbers together, and all the variables

4y+5(y-6)-(-10(-1y+9))=0

We multiply parentheses

4y+5y-(-10(-1y+9))-30=0



We calculate terms in parentheses: -(-10(-1y+9)), so:

-10(-1y+9)

We multiply parentheses

10y-90

Back to the equation:

-(10y-90)



We add all the numbers together, and all the variables

9y-(10y-90)-30=0

We get rid of parentheses

9y-10y+90-30=0

We add all the numbers together, and all the variables

-1y+60=0

We move all terms containing y to the left, all other terms to the right

-y=-60

y=-60/-1

y=+60

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