5(y-7)-3=3(y+4)

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Solution for 5(y-7)-3=3(y+4) equation: 



5(y-7)-3=3(y+4)

We move all terms to the left:

5(y-7)-3-(3(y+4))=0

We multiply parentheses

5y-(3(y+4))-35-3=0



We calculate terms in parentheses: -(3(y+4)), so:

3(y+4)

We multiply parentheses

3y+12

Back to the equation:

-(3y+12)



We add all the numbers together, and all the variables

5y-(3y+12)-38=0

We get rid of parentheses

5y-3y-12-38=0

We add all the numbers together, and all the variables

2y-50=0

We move all terms containing y to the left, all other terms to the right

2y=50

y=50/2

y=25

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