5(y/3)+2=2(y/3)+3y

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Solution for 5(y/3)+2=2(y/3)+3y equation: 



5(y/3)+2=2(y/3)+3y

We move all terms to the left:

5(y/3)+2-(2(y/3)+3y)=0



Domain of the equation: 3)+3y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

5(+y/3)-(2(+y/3)+3y)+2=0

We multiply parentheses

5y-(2(+y/3)+3y)+2=0

We multiply all the terms by the denominator


5y*3)+3y)-(2(+y+2*3)+3y)=0

We add all the numbers together, and all the variables

5y*3)+3y)-(2(y+6)+3y)=0

Wy multiply elements

15y^2+6)+3y)=0

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