5(z+1)=14=19-22+7z

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Solution for 5(z+1)=14=19-22+7z equation: 



5(z+1)=14=19-22+7z

We move all terms to the left:

5(z+1)-(14)=0

We multiply parentheses

5z+5-14=0

We add all the numbers together, and all the variables

5z-9=0

We move all terms containing z to the left, all other terms to the right

5z=9

z=9/5

z=1+4/5

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