5(z+1)=2(3-2z)+17

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Solution for 5(z+1)=2(3-2z)+17 equation:


Simplifying
5(z + 1) = 2(3 + -2z) + 17

Reorder the terms:
5(1 + z) = 2(3 + -2z) + 17
(1 * 5 + z * 5) = 2(3 + -2z) + 17
(5 + 5z) = 2(3 + -2z) + 17
5 + 5z = (3 * 2 + -2z * 2) + 17
5 + 5z = (6 + -4z) + 17

Reorder the terms:
5 + 5z = 6 + 17 + -4z

Combine like terms: 6 + 17 = 23
5 + 5z = 23 + -4z

Solving
5 + 5z = 23 + -4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '4z' to each side of the equation.
5 + 5z + 4z = 23 + -4z + 4z

Combine like terms: 5z + 4z = 9z
5 + 9z = 23 + -4z + 4z

Combine like terms: -4z + 4z = 0
5 + 9z = 23 + 0
5 + 9z = 23

Add '-5' to each side of the equation.
5 + -5 + 9z = 23 + -5

Combine like terms: 5 + -5 = 0
0 + 9z = 23 + -5
9z = 23 + -5

Combine like terms: 23 + -5 = 18
9z = 18

Divide each side by '9'.
z = 2

Simplifying
z = 2

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