5(z+1)=2(3-z)+17

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Solution for 5(z+1)=2(3-z)+17 equation: 



5(z+1)=2(3-z)+17

We move all terms to the left:

5(z+1)-(2(3-z)+17)=0

We add all the numbers together, and all the variables

5(z+1)-(2(-1z+3)+17)=0

We multiply parentheses

5z-(2(-1z+3)+17)+5=0



We calculate terms in parentheses: -(2(-1z+3)+17), so:

2(-1z+3)+17

We multiply parentheses

-2z+6+17

We add all the numbers together, and all the variables

-2z+23

Back to the equation:

-(-2z+23)



We get rid of parentheses

5z+2z-23+5=0

We add all the numbers together, and all the variables

7z-18=0

We move all terms containing z to the left, all other terms to the right

7z=18

z=18/7

z=2+4/7

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