5(z+1)=2(3-z)+17

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Solution for 5(z+1)=2(3-z)+17 equation:



5(z+1)=2(3-z)+17
We move all terms to the left:
5(z+1)-(2(3-z)+17)=0
We add all the numbers together, and all the variables
5(z+1)-(2(-1z+3)+17)=0
We multiply parentheses
5z-(2(-1z+3)+17)+5=0
We calculate terms in parentheses: -(2(-1z+3)+17), so:
2(-1z+3)+17
We multiply parentheses
-2z+6+17
We add all the numbers together, and all the variables
-2z+23
Back to the equation:
-(-2z+23)
We get rid of parentheses
5z+2z-23+5=0
We add all the numbers together, and all the variables
7z-18=0
We move all terms containing z to the left, all other terms to the right
7z=18
z=18/7
z=2+4/7

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