5(z+1)=3(2+3)+11

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Solution for 5(z+1)=3(2+3)+11 equation:



5(z+1)=3(2+3)+11
We move all terms to the left:
5(z+1)-(3(2+3)+11)=0
We add all the numbers together, and all the variables
5(z+1)-(35+11)=0
We add all the numbers together, and all the variables
5(z+1)-46=0
We multiply parentheses
5z+5-46=0
We add all the numbers together, and all the variables
5z-41=0
We move all terms containing z to the left, all other terms to the right
5z=41
z=41/5
z=8+1/5

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