5(z+1)=3(2+z)+11

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Solution for 5(z+1)=3(2+z)+11 equation: 



5(z+1)=3(2+z)+11

We move all terms to the left:

5(z+1)-(3(2+z)+11)=0

We add all the numbers together, and all the variables

5(z+1)-(3(z+2)+11)=0

We multiply parentheses

5z-(3(z+2)+11)+5=0



We calculate terms in parentheses: -(3(z+2)+11), so:

3(z+2)+11

We multiply parentheses

3z+6+11

We add all the numbers together, and all the variables

3z+17

Back to the equation:

-(3z+17)



We get rid of parentheses

5z-3z-17+5=0

We add all the numbers together, and all the variables

2z-12=0

We move all terms containing z to the left, all other terms to the right

2z=12

z=12/2

z=6

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