5(z+1)=3(z+2)+11.0z

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Solution for 5(z+1)=3(z+2)+11.0z equation:



5(z+1)=3(z+2)+11.0z
We move all terms to the left:
5(z+1)-(3(z+2)+11.0z)=0
We multiply parentheses
5z-(3(z+2)+11.0z)+5=0
We calculate terms in parentheses: -(3(z+2)+11.0z), so:
3(z+2)+11.0z
We add all the numbers together, and all the variables
11.0z+3(z+2)
We multiply parentheses
11.0z+3z+6
We add all the numbers together, and all the variables
14z+6
Back to the equation:
-(14z+6)
We get rid of parentheses
5z-14z-6+5=0
We add all the numbers together, and all the variables
-9z-1=0
We move all terms containing z to the left, all other terms to the right
-9z=1
z=1/-9
z=-1/9

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