5(z+1)=3(z+2)+11.z

Solution for 5(z+1)=3(z+2)+11.z equation:

5(z+1)=3(z+2)+11.z

We move all terms to the left:

5(z+1)-(3(z+2)+11.z)=0

We multiply parentheses

5z-(3(z+2)+11.z)+5=0


We calculate terms in parentheses: -(3(z+2)+11.z), so:

3(z+2)+11.z

We add all the numbers together, and all the variables

11.z+3(z+2)

We multiply parentheses

11.z+3z+6

We add all the numbers together, and all the variables

14z+6

Back to the equation:

-(14z+6)


We get rid of parentheses

5z-14z-6+5=0

We add all the numbers together, and all the variables

-9z-1=0

We move all terms containing z to the left, all other terms to the right

-9z=1

z=1/-9

z=-1/9