5(z+1)=3(z+2)=11

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Solution for 5(z+1)=3(z+2)=11 equation: 



5(z+1)=3(z+2)=11

We move all terms to the left:

5(z+1)-(3(z+2))=0

We multiply parentheses

5z-(3(z+2))+5=0



We calculate terms in parentheses: -(3(z+2)), so:

3(z+2)

We multiply parentheses

3z+6

Back to the equation:

-(3z+6)



We get rid of parentheses

5z-3z-6+5=0

We add all the numbers together, and all the variables

2z-1=0

We move all terms containing z to the left, all other terms to the right

2z=1

z=1/2

z=1/2

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