5(z+1)=4(z-6)+2

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Solution for 5(z+1)=4(z-6)+2 equation: 



5(z+1)=4(z-6)+2

We move all terms to the left:

5(z+1)-(4(z-6)+2)=0

We multiply parentheses

5z-(4(z-6)+2)+5=0



We calculate terms in parentheses: -(4(z-6)+2), so:

4(z-6)+2

We multiply parentheses

4z-24+2

We add all the numbers together, and all the variables

4z-22

Back to the equation:

-(4z-22)



We get rid of parentheses

5z-4z+22+5=0

We add all the numbers together, and all the variables

z+27=0

We move all terms containing z to the left, all other terms to the right

z=-27

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