5(z+1)=4(z-8)+z

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Solution for 5(z+1)=4(z-8)+z equation:


Simplifying
5(z + 1) = 4(z + -8) + z

Reorder the terms:
5(1 + z) = 4(z + -8) + z
(1 * 5 + z * 5) = 4(z + -8) + z
(5 + 5z) = 4(z + -8) + z

Reorder the terms:
5 + 5z = 4(-8 + z) + z
5 + 5z = (-8 * 4 + z * 4) + z
5 + 5z = (-32 + 4z) + z

Combine like terms: 4z + z = 5z
5 + 5z = -32 + 5z

Add '-5z' to each side of the equation.
5 + 5z + -5z = -32 + 5z + -5z

Combine like terms: 5z + -5z = 0
5 + 0 = -32 + 5z + -5z
5 = -32 + 5z + -5z

Combine like terms: 5z + -5z = 0
5 = -32 + 0
5 = -32

Solving
5 = -32

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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