5(z+2)-(2+2z)=2z

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Solution for 5(z+2)-(2+2z)=2z equation:


Simplifying
5(z + 2) + -1(2 + 2z) = 2z

Reorder the terms:
5(2 + z) + -1(2 + 2z) = 2z
(2 * 5 + z * 5) + -1(2 + 2z) = 2z
(10 + 5z) + -1(2 + 2z) = 2z
10 + 5z + (2 * -1 + 2z * -1) = 2z
10 + 5z + (-2 + -2z) = 2z

Reorder the terms:
10 + -2 + 5z + -2z = 2z

Combine like terms: 10 + -2 = 8
8 + 5z + -2z = 2z

Combine like terms: 5z + -2z = 3z
8 + 3z = 2z

Solving
8 + 3z = 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
8 + 3z + -2z = 2z + -2z

Combine like terms: 3z + -2z = 1z
8 + 1z = 2z + -2z

Combine like terms: 2z + -2z = 0
8 + 1z = 0

Add '-8' to each side of the equation.
8 + -8 + 1z = 0 + -8

Combine like terms: 8 + -8 = 0
0 + 1z = 0 + -8
1z = 0 + -8

Combine like terms: 0 + -8 = -8
1z = -8

Divide each side by '1'.
z = -8

Simplifying
z = -8

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