5(z+2)-3z=-4(-(1/2)z+1)+14

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Solution for 5(z+2)-3z=-4(-(1/2)z+1)+14 equation: 



5(z+2)-3z=-4(-(1/2)z+1)+14

We move all terms to the left:

5(z+2)-3z-(-4(-(1/2)z+1)+14)=0



Domain of the equation: 2)z+1)+14)!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

5(z+2)-3z-(-4(-(+1/2)z+1)+14)=0

We add all the numbers together, and all the variables

-3z+5(z+2)-(-4(-(+1/2)z+1)+14)=0

We multiply parentheses

-3z+5z-(-4(-(+1/2)z+1)+14)+10=0

We multiply all the terms by the denominator


-3z*2)z+1)+14)+5z*2)z+1)+14)-(-4(-(+1+10*2)z+1)+14)=0

We add all the numbers together, and all the variables

-3z*2)z+1)+14)+5z*2)z+1)+14)-(-4(-21z+1)+14)=0

Wy multiply elements

-12z^3=0

We do not support ezpression: z^3

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