5(z+2)=3(z+1)+11+z

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Solution for 5(z+2)=3(z+1)+11+z equation: 



5(z+2)=3(z+1)+11+z

We move all terms to the left:

5(z+2)-(3(z+1)+11+z)=0

We multiply parentheses

5z-(3(z+1)+11+z)+10=0



We calculate terms in parentheses: -(3(z+1)+11+z), so:

3(z+1)+11+z

determiningTheFunctionDomain
3(z+1)+z+11

We add all the numbers together, and all the variables

z+3(z+1)+11

We multiply parentheses

z+3z+3+11

We add all the numbers together, and all the variables

4z+14

Back to the equation:

-(4z+14)



We get rid of parentheses

5z-4z-14+10=0

We add all the numbers together, and all the variables

z-4=0

We move all terms containing z to the left, all other terms to the right

z=4

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