5(z+2)=3(z+1)-5

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Solution for 5(z+2)=3(z+1)-5 equation: 


Simplifying
5(z + 2) = 3(z + 1) + -5

Reorder the terms:
5(2 + z) = 3(z + 1) + -5
(2 * 5 + z * 5) = 3(z + 1) + -5
(10 + 5z) = 3(z + 1) + -5

Reorder the terms:
10 + 5z = 3(1 + z) + -5
10 + 5z = (1 * 3 + z * 3) + -5
10 + 5z = (3 + 3z) + -5

Reorder the terms:
10 + 5z = 3 + -5 + 3z

Combine like terms: 3 + -5 = -2
10 + 5z = -2 + 3z

Solving
10 + 5z = -2 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
10 + 5z + -3z = -2 + 3z + -3z

Combine like terms: 5z + -3z = 2z
10 + 2z = -2 + 3z + -3z

Combine like terms: 3z + -3z = 0
10 + 2z = -2 + 0
10 + 2z = -2

Add '-10' to each side of the equation.
10 + -10 + 2z = -2 + -10

Combine like terms: 10 + -10 = 0
0 + 2z = -2 + -10
2z = -2 + -10

Combine like terms: -2 + -10 = -12
2z = -12

Divide each side by '2'.
z = -6

Simplifying
z = -6

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