5(z+2)=6(2z-3)

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Solution for 5(z+2)=6(2z-3) equation:


Simplifying
5(z + 2) = 6(2z + -3)

Reorder the terms:
5(2 + z) = 6(2z + -3)
(2 * 5 + z * 5) = 6(2z + -3)
(10 + 5z) = 6(2z + -3)

Reorder the terms:
10 + 5z = 6(-3 + 2z)
10 + 5z = (-3 * 6 + 2z * 6)
10 + 5z = (-18 + 12z)

Solving
10 + 5z = -18 + 12z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-12z' to each side of the equation.
10 + 5z + -12z = -18 + 12z + -12z

Combine like terms: 5z + -12z = -7z
10 + -7z = -18 + 12z + -12z

Combine like terms: 12z + -12z = 0
10 + -7z = -18 + 0
10 + -7z = -18

Add '-10' to each side of the equation.
10 + -10 + -7z = -18 + -10

Combine like terms: 10 + -10 = 0
0 + -7z = -18 + -10
-7z = -18 + -10

Combine like terms: -18 + -10 = -28
-7z = -28

Divide each side by '-7'.
z = 4

Simplifying
z = 4

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