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5(z+3)+2(z-1)=3z-11
We move all terms to the left:
5(z+3)+2(z-1)-(3z-11)=0
We multiply parentheses
5z+2z-(3z-11)+15-2=0
We get rid of parentheses
5z+2z-3z+11+15-2=0
We add all the numbers together, and all the variables
4z+24=0
We move all terms containing z to the left, all other terms to the right
4z=-24
z=-24/4
z=-6
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