5(z+3)-4(1+p)=

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Solution for 5(z+3)-4(1+p)= equation:


Simplifying
5(z + 3) + -4(1 + p) = 0

Reorder the terms:
5(3 + z) + -4(1 + p) = 0
(3 * 5 + z * 5) + -4(1 + p) = 0
(15 + 5z) + -4(1 + p) = 0
15 + 5z + (1 * -4 + p * -4) = 0
15 + 5z + (-4 + -4p) = 0

Reorder the terms:
15 + -4 + -4p + 5z = 0

Combine like terms: 15 + -4 = 11
11 + -4p + 5z = 0

Solving
11 + -4p + 5z = 0

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '-11' to each side of the equation.
11 + -4p + -11 + 5z = 0 + -11

Reorder the terms:
11 + -11 + -4p + 5z = 0 + -11

Combine like terms: 11 + -11 = 0
0 + -4p + 5z = 0 + -11
-4p + 5z = 0 + -11

Combine like terms: 0 + -11 = -11
-4p + 5z = -11

Add '-5z' to each side of the equation.
-4p + 5z + -5z = -11 + -5z

Combine like terms: 5z + -5z = 0
-4p + 0 = -11 + -5z
-4p = -11 + -5z

Divide each side by '-4'.
p = 2.75 + 1.25z

Simplifying
p = 2.75 + 1.25z

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