5(z+3)=4(2z+1)

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Solution for 5(z+3)=4(2z+1) equation:


Simplifying
5(z + 3) = 4(2z + 1)

Reorder the terms:
5(3 + z) = 4(2z + 1)
(3 * 5 + z * 5) = 4(2z + 1)
(15 + 5z) = 4(2z + 1)

Reorder the terms:
15 + 5z = 4(1 + 2z)
15 + 5z = (1 * 4 + 2z * 4)
15 + 5z = (4 + 8z)

Solving
15 + 5z = 4 + 8z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-8z' to each side of the equation.
15 + 5z + -8z = 4 + 8z + -8z

Combine like terms: 5z + -8z = -3z
15 + -3z = 4 + 8z + -8z

Combine like terms: 8z + -8z = 0
15 + -3z = 4 + 0
15 + -3z = 4

Add '-15' to each side of the equation.
15 + -15 + -3z = 4 + -15

Combine like terms: 15 + -15 = 0
0 + -3z = 4 + -15
-3z = 4 + -15

Combine like terms: 4 + -15 = -11
-3z = -11

Divide each side by '-3'.
z = 3.666666667

Simplifying
z = 3.666666667

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