5(z+4)+1=7-(z+4)

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Solution for 5(z+4)+1=7-(z+4) equation:


Simplifying
5(z + 4) + 1 = 7 + -1(z + 4)

Reorder the terms:
5(4 + z) + 1 = 7 + -1(z + 4)
(4 * 5 + z * 5) + 1 = 7 + -1(z + 4)
(20 + 5z) + 1 = 7 + -1(z + 4)

Reorder the terms:
20 + 1 + 5z = 7 + -1(z + 4)

Combine like terms: 20 + 1 = 21
21 + 5z = 7 + -1(z + 4)

Reorder the terms:
21 + 5z = 7 + -1(4 + z)
21 + 5z = 7 + (4 * -1 + z * -1)
21 + 5z = 7 + (-4 + -1z)

Combine like terms: 7 + -4 = 3
21 + 5z = 3 + -1z

Solving
21 + 5z = 3 + -1z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add 'z' to each side of the equation.
21 + 5z + z = 3 + -1z + z

Combine like terms: 5z + z = 6z
21 + 6z = 3 + -1z + z

Combine like terms: -1z + z = 0
21 + 6z = 3 + 0
21 + 6z = 3

Add '-21' to each side of the equation.
21 + -21 + 6z = 3 + -21

Combine like terms: 21 + -21 = 0
0 + 6z = 3 + -21
6z = 3 + -21

Combine like terms: 3 + -21 = -18
6z = -18

Divide each side by '6'.
z = -3

Simplifying
z = -3

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