5(z+4)-13=2z+19

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Solution for 5(z+4)-13=2z+19 equation:


Simplifying
5(z + 4) + -13 = 2z + 19

Reorder the terms:
5(4 + z) + -13 = 2z + 19
(4 * 5 + z * 5) + -13 = 2z + 19
(20 + 5z) + -13 = 2z + 19

Reorder the terms:
20 + -13 + 5z = 2z + 19

Combine like terms: 20 + -13 = 7
7 + 5z = 2z + 19

Reorder the terms:
7 + 5z = 19 + 2z

Solving
7 + 5z = 19 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
7 + 5z + -2z = 19 + 2z + -2z

Combine like terms: 5z + -2z = 3z
7 + 3z = 19 + 2z + -2z

Combine like terms: 2z + -2z = 0
7 + 3z = 19 + 0
7 + 3z = 19

Add '-7' to each side of the equation.
7 + -7 + 3z = 19 + -7

Combine like terms: 7 + -7 = 0
0 + 3z = 19 + -7
3z = 19 + -7

Combine like terms: 19 + -7 = 12
3z = 12

Divide each side by '3'.
z = 4

Simplifying
z = 4

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