5(z+4)=21

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Solution for 5(z+4)=21 equation: 



5(z+4)=21

We move all terms to the left:

5(z+4)-(21)=0

We multiply parentheses

5z+20-21=0

We add all the numbers together, and all the variables

5z-1=0

We move all terms containing z to the left, all other terms to the right

5z=1

z=1/5

z=1/5

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