5(z+8)=4(z-5)+z

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Solution for 5(z+8)=4(z-5)+z equation:



5(z+8)=4(z-5)+z
We move all terms to the left:
5(z+8)-(4(z-5)+z)=0
We multiply parentheses
5z-(4(z-5)+z)+40=0
We calculate terms in parentheses: -(4(z-5)+z), so:
4(z-5)+z
We add all the numbers together, and all the variables
z+4(z-5)
We multiply parentheses
z+4z-20
We add all the numbers together, and all the variables
5z-20
Back to the equation:
-(5z-20)
We get rid of parentheses
5z-5z+20+40=0
We add all the numbers together, and all the variables
60!=0
There is no solution for this equation

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