5(z-1)-2(z+4)=2(z+1)

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Solution for 5(z-1)-2(z+4)=2(z+1) equation:


Simplifying
5(z + -1) + -2(z + 4) = 2(z + 1)

Reorder the terms:
5(-1 + z) + -2(z + 4) = 2(z + 1)
(-1 * 5 + z * 5) + -2(z + 4) = 2(z + 1)
(-5 + 5z) + -2(z + 4) = 2(z + 1)

Reorder the terms:
-5 + 5z + -2(4 + z) = 2(z + 1)
-5 + 5z + (4 * -2 + z * -2) = 2(z + 1)
-5 + 5z + (-8 + -2z) = 2(z + 1)

Reorder the terms:
-5 + -8 + 5z + -2z = 2(z + 1)

Combine like terms: -5 + -8 = -13
-13 + 5z + -2z = 2(z + 1)

Combine like terms: 5z + -2z = 3z
-13 + 3z = 2(z + 1)

Reorder the terms:
-13 + 3z = 2(1 + z)
-13 + 3z = (1 * 2 + z * 2)
-13 + 3z = (2 + 2z)

Solving
-13 + 3z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-13 + 3z + -2z = 2 + 2z + -2z

Combine like terms: 3z + -2z = 1z
-13 + 1z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-13 + 1z = 2 + 0
-13 + 1z = 2

Add '13' to each side of the equation.
-13 + 13 + 1z = 2 + 13

Combine like terms: -13 + 13 = 0
0 + 1z = 2 + 13
1z = 2 + 13

Combine like terms: 2 + 13 = 15
1z = 15

Divide each side by '1'.
z = 15

Simplifying
z = 15

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