5(z-1)=2(z-4)-6

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Solution for 5(z-1)=2(z-4)-6 equation: 



5(z-1)=2(z-4)-6

We move all terms to the left:

5(z-1)-(2(z-4)-6)=0

We multiply parentheses

5z-(2(z-4)-6)-5=0



We calculate terms in parentheses: -(2(z-4)-6), so:

2(z-4)-6

We multiply parentheses

2z-8-6

We add all the numbers together, and all the variables

2z-14

Back to the equation:

-(2z-14)



We get rid of parentheses

5z-2z+14-5=0

We add all the numbers together, and all the variables

3z+9=0

We move all terms containing z to the left, all other terms to the right

3z=-9

z=-9/3

z=-3

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