5(z-1)=4(z+3)

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Solution for 5(z-1)=4(z+3) equation:


Simplifying
5(z + -1) = 4(z + 3)

Reorder the terms:
5(-1 + z) = 4(z + 3)
(-1 * 5 + z * 5) = 4(z + 3)
(-5 + 5z) = 4(z + 3)

Reorder the terms:
-5 + 5z = 4(3 + z)
-5 + 5z = (3 * 4 + z * 4)
-5 + 5z = (12 + 4z)

Solving
-5 + 5z = 12 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-5 + 5z + -4z = 12 + 4z + -4z

Combine like terms: 5z + -4z = 1z
-5 + 1z = 12 + 4z + -4z

Combine like terms: 4z + -4z = 0
-5 + 1z = 12 + 0
-5 + 1z = 12

Add '5' to each side of the equation.
-5 + 5 + 1z = 12 + 5

Combine like terms: -5 + 5 = 0
0 + 1z = 12 + 5
1z = 12 + 5

Combine like terms: 12 + 5 = 17
1z = 17

Divide each side by '1'.
z = 17

Simplifying
z = 17

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