5(z-1)=4(z+4)

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Solution for 5(z-1)=4(z+4) equation:


Simplifying
5(z + -1) = 4(z + 4)

Reorder the terms:
5(-1 + z) = 4(z + 4)
(-1 * 5 + z * 5) = 4(z + 4)
(-5 + 5z) = 4(z + 4)

Reorder the terms:
-5 + 5z = 4(4 + z)
-5 + 5z = (4 * 4 + z * 4)
-5 + 5z = (16 + 4z)

Solving
-5 + 5z = 16 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-5 + 5z + -4z = 16 + 4z + -4z

Combine like terms: 5z + -4z = 1z
-5 + 1z = 16 + 4z + -4z

Combine like terms: 4z + -4z = 0
-5 + 1z = 16 + 0
-5 + 1z = 16

Add '5' to each side of the equation.
-5 + 5 + 1z = 16 + 5

Combine like terms: -5 + 5 = 0
0 + 1z = 16 + 5
1z = 16 + 5

Combine like terms: 16 + 5 = 21
1z = 21

Divide each side by '1'.
z = 21

Simplifying
z = 21

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