5(z-2)=-2(z+1)+6

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Solution for 5(z-2)=-2(z+1)+6 equation:



5(z-2)=-2(z+1)+6
We move all terms to the left:
5(z-2)-(-2(z+1)+6)=0
We multiply parentheses
5z-(-2(z+1)+6)-10=0
We calculate terms in parentheses: -(-2(z+1)+6), so:
-2(z+1)+6
We multiply parentheses
-2z-2+6
We add all the numbers together, and all the variables
-2z+4
Back to the equation:
-(-2z+4)
We get rid of parentheses
5z+2z-4-10=0
We add all the numbers together, and all the variables
7z-14=0
We move all terms containing z to the left, all other terms to the right
7z=14
z=14/7
z=2

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