5(z-2)=2(3z+4)+z

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Solution for 5(z-2)=2(3z+4)+z equation: 



5(z-2)=2(3z+4)+z

We move all terms to the left:

5(z-2)-(2(3z+4)+z)=0

We multiply parentheses

5z-(2(3z+4)+z)-10=0



We calculate terms in parentheses: -(2(3z+4)+z), so:

2(3z+4)+z

We add all the numbers together, and all the variables

z+2(3z+4)

We multiply parentheses

z+6z+8

We add all the numbers together, and all the variables

7z+8

Back to the equation:

-(7z+8)



We get rid of parentheses

5z-7z-8-10=0

We add all the numbers together, and all the variables

-2z-18=0

We move all terms containing z to the left, all other terms to the right

-2z=18

z=18/-2

z=-9

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