5(z-2)=3(3z+1)-2z

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Solution for 5(z-2)=3(3z+1)-2z equation: 



5(z-2)=3(3z+1)-2z

We move all terms to the left:

5(z-2)-(3(3z+1)-2z)=0

We multiply parentheses

5z-(3(3z+1)-2z)-10=0



We calculate terms in parentheses: -(3(3z+1)-2z), so:

3(3z+1)-2z

We add all the numbers together, and all the variables

-2z+3(3z+1)

We multiply parentheses

-2z+9z+3

We add all the numbers together, and all the variables

7z+3

Back to the equation:

-(7z+3)



We get rid of parentheses

5z-7z-3-10=0

We add all the numbers together, and all the variables

-2z-13=0

We move all terms containing z to the left, all other terms to the right

-2z=13

z=13/-2

z=-6+1/2

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