5(z-4)+13=3(z+7)

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Solution for 5(z-4)+13=3(z+7) equation:


Simplifying
5(z + -4) + 13 = 3(z + 7)

Reorder the terms:
5(-4 + z) + 13 = 3(z + 7)
(-4 * 5 + z * 5) + 13 = 3(z + 7)
(-20 + 5z) + 13 = 3(z + 7)

Reorder the terms:
-20 + 13 + 5z = 3(z + 7)

Combine like terms: -20 + 13 = -7
-7 + 5z = 3(z + 7)

Reorder the terms:
-7 + 5z = 3(7 + z)
-7 + 5z = (7 * 3 + z * 3)
-7 + 5z = (21 + 3z)

Solving
-7 + 5z = 21 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-7 + 5z + -3z = 21 + 3z + -3z

Combine like terms: 5z + -3z = 2z
-7 + 2z = 21 + 3z + -3z

Combine like terms: 3z + -3z = 0
-7 + 2z = 21 + 0
-7 + 2z = 21

Add '7' to each side of the equation.
-7 + 7 + 2z = 21 + 7

Combine like terms: -7 + 7 = 0
0 + 2z = 21 + 7
2z = 21 + 7

Combine like terms: 21 + 7 = 28
2z = 28

Divide each side by '2'.
z = 14

Simplifying
z = 14

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