5(z-4)+z=6(z-2)-8

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Solution for 5(z-4)+z=6(z-2)-8 equation:


Simplifying
5(z + -4) + z = 6(z + -2) + -8

Reorder the terms:
5(-4 + z) + z = 6(z + -2) + -8
(-4 * 5 + z * 5) + z = 6(z + -2) + -8
(-20 + 5z) + z = 6(z + -2) + -8

Combine like terms: 5z + z = 6z
-20 + 6z = 6(z + -2) + -8

Reorder the terms:
-20 + 6z = 6(-2 + z) + -8
-20 + 6z = (-2 * 6 + z * 6) + -8
-20 + 6z = (-12 + 6z) + -8

Reorder the terms:
-20 + 6z = -12 + -8 + 6z

Combine like terms: -12 + -8 = -20
-20 + 6z = -20 + 6z

Add '20' to each side of the equation.
-20 + 20 + 6z = -20 + 20 + 6z

Combine like terms: -20 + 20 = 0
0 + 6z = -20 + 20 + 6z
6z = -20 + 20 + 6z

Combine like terms: -20 + 20 = 0
6z = 0 + 6z
6z = 6z

Add '-6z' to each side of the equation.
6z + -6z = 6z + -6z

Combine like terms: 6z + -6z = 0
0 = 6z + -6z

Combine like terms: 6z + -6z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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