5(z-4)-z=4z-20

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Solution for 5(z-4)-z=4z-20 equation:


Simplifying
5(z + -4) + -1z = 4z + -20

Reorder the terms:
5(-4 + z) + -1z = 4z + -20
(-4 * 5 + z * 5) + -1z = 4z + -20
(-20 + 5z) + -1z = 4z + -20

Combine like terms: 5z + -1z = 4z
-20 + 4z = 4z + -20

Reorder the terms:
-20 + 4z = -20 + 4z

Add '20' to each side of the equation.
-20 + 20 + 4z = -20 + 20 + 4z

Combine like terms: -20 + 20 = 0
0 + 4z = -20 + 20 + 4z
4z = -20 + 20 + 4z

Combine like terms: -20 + 20 = 0
4z = 0 + 4z
4z = 4z

Add '-4z' to each side of the equation.
4z + -4z = 4z + -4z

Combine like terms: 4z + -4z = 0
0 = 4z + -4z

Combine like terms: 4z + -4z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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