5(z-4)=-2(3-z)

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Solution for 5(z-4)=-2(3-z) equation:



5(z-4)=-2(3-z)
We move all terms to the left:
5(z-4)-(-2(3-z))=0
We add all the numbers together, and all the variables
5(z-4)-(-2(-1z+3))=0
We multiply parentheses
5z-(-2(-1z+3))-20=0
We calculate terms in parentheses: -(-2(-1z+3)), so:
-2(-1z+3)
We multiply parentheses
2z-6
Back to the equation:
-(2z-6)
We get rid of parentheses
5z-2z+6-20=0
We add all the numbers together, and all the variables
3z-14=0
We move all terms containing z to the left, all other terms to the right
3z=14
z=14/3
z=4+2/3

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