5(z-4)=2(2z+4)

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Solution for 5(z-4)=2(2z+4) equation: 



5(z-4)=2(2z+4)

We move all terms to the left:

5(z-4)-(2(2z+4))=0

We multiply parentheses

5z-(2(2z+4))-20=0



We calculate terms in parentheses: -(2(2z+4)), so:

2(2z+4)

We multiply parentheses

4z+8

Back to the equation:

-(4z+8)



We get rid of parentheses

5z-4z-8-20=0

We add all the numbers together, and all the variables

z-28=0

We move all terms containing z to the left, all other terms to the right

z=28

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