5(z-4)=3(z+2)

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Solution for 5(z-4)=3(z+2) equation:


Simplifying
5(z + -4) = 3(z + 2)

Reorder the terms:
5(-4 + z) = 3(z + 2)
(-4 * 5 + z * 5) = 3(z + 2)
(-20 + 5z) = 3(z + 2)

Reorder the terms:
-20 + 5z = 3(2 + z)
-20 + 5z = (2 * 3 + z * 3)
-20 + 5z = (6 + 3z)

Solving
-20 + 5z = 6 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-20 + 5z + -3z = 6 + 3z + -3z

Combine like terms: 5z + -3z = 2z
-20 + 2z = 6 + 3z + -3z

Combine like terms: 3z + -3z = 0
-20 + 2z = 6 + 0
-20 + 2z = 6

Add '20' to each side of the equation.
-20 + 20 + 2z = 6 + 20

Combine like terms: -20 + 20 = 0
0 + 2z = 6 + 20
2z = 6 + 20

Combine like terms: 6 + 20 = 26
2z = 26

Divide each side by '2'.
z = 13

Simplifying
z = 13

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